116 g of a substance upon dissociation reaction, yields 7.5 g of hydrogen, 60 g of oxygen and 48.5 g of carbon. Given that the atomic masses of H, O and C are 1, 16 and 12, respectively. The data agrees with how many formulae of the following? A. CH_(3)COOH, B. HCHO, C. CH_(3)OOCH_(3), D. CH_(3)CHO

\% H=(7.5 / 116) x 100=6.5 \ \% O=(60 / 116) x 100=51.7 \ \% C=(48.5 / 116) x 100=41.8 Relative atomicities = H => 6.5 O => (51.7 / 16)=3.25 \ C => (41.8 / 12)=3.5 Emperically formula is approx.. CH_2 O (A) C_2 H_4 O_2 (B) CH_2 O relate to this formula.

116 g of a substance upon dissociation reaction yields ... | null (Chemistry)

\begin{aligned} &\% \mathrm{H}=\frac{7.5}{116} \times 100=6.5 \\\\ &\% \mathrm{O}=\frac{60}{116} \times 100=51.7 \\\\ &\% \mathrm{C}=\frac{48.5}{116} \times 100=41.8 \end{aligned}

Relative atomicities

=\mathrm{H} \Rightarrow 6.5

\begin{aligned} &\mathrm{O} \Rightarrow \frac{51.7}{16}=3.25 \\\\ &\mathrm{C} \Rightarrow \frac{41.8}{12}=3.5 \end{aligned}

Emperically formula is approx..

\mathrm{CH}_2 \mathrm{O}

(A)

\mathrm{C}_2 \mathrm{H}_4 \mathrm{O}_2

(B)

\mathrm{CH}_2 \mathrm{O}

relate to this formula.

Explanation

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