To determine the total sum of oxygen atoms and

electrons in vanillin, let's first consider the structure of vanillin. Vanillin is an organic compound with the chemical formula . It consists of a benzene ring attached to a methoxy group (-OCH₃), a hydroxyl group (-OH), and an aldehyde group (-CHO).

Firstly, let's count the oxygen atoms:

• One from the methoxy group (-OCH₃)
• One from the hydroxyl group (-OH)
• One from the aldehyde group (-CHO)

Thus, there are a total of 3 oxygen atoms in vanillin.

Next, let's calculate the total number of

electrons:

• The benzene ring has 3 double bonds, contributing 6
  $$\pi$$
  electrons.
• The aldehyde group has 1 double bond (C=O), contributing 2
  $$\pi$$
  electrons.
• The methoxy group and the hydroxyl group do not contribute any
  $$\pi$$
  electrons since they do not have
  $$\pi$$
  bonds in their structures.

Therefore, vanillin has a total of 8

electrons from the benzene ring and the aldehyde group.

Adding the number of oxygen atoms (3) and the

electrons (8) gives us a total sum of 11.

Thus, the total sum of oxygen atoms and

electrons in vanillin is 11.