Two cars A and B each of mass 10^3 kg are moving on parallel tracks separated by a distance of 10 m , in same direction with speeds 72 km / h and 36 km / h. The magnitude of angular momentum of car A with respect to car B is \_\_\_\_ J.s.

L= m . V_ rel r_perp \ =1000 x (36 x (5 / 18)) x 10 \ =10^5 kg m^2 / s \

Two cars A and B each of mass 10 3 kg are moving on par... | null (Physics) | DivineJEE

JEE Mains 2026 21st January Shift 2

Physics

Two cars A and B each of mass

10^{3} \mathrm{~kg}

are moving on parallel tracks separated by a distance of 10 m , in same direction with speeds

72 \mathrm{~km} / \mathrm{h}

and

36 \mathrm{~km} / \mathrm{h}

. The magnitude of angular momentum of car A with respect to car B is

\_\_\_\_

J.s.

3.6 \times 10^{5}

10^{5}

3 \times 10^{5}

2 \times 10^{5}

Correct Answer:

\mathrm{L}=\mathrm{m} . \mathrm{V}_{\text {rel }} \mathrm{r}_{\perp}

\\ \begin{aligned} & =1000 \times\left(36 \times \frac{5}{18}\right) \times 10 \\ & =10^{5} \mathrm{~kg} \mathrm{~m}^{2} / \mathrm{s} \end{aligned}

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