The vapour pressures of A and B at 25 C are 90 mm Hg and 15

Question

The vapour pressures of A and B at 25^°C are 90 mm Hg and 15 mm Hg respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x x 10^(-1). The value of x is ___________. (Nearest integer)

DivineJEE · Accepted Answer

x_(A) = 0.6P_(T) = x_(A)P_(A)^(o) + x_(B)P_(B)^(o)= 0.6 x 90 + 0.4 x 15= 54 + 6 = 60x_(A)P_(A)^(o) = y_(A)P_(T)0.6 x 90 = y_(A)(60) => y_(A) = 0.9y_(B) = 0.1 = 1 x 10^(-1)Therefore x = 1

Explanation

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