The reaction 2 NO+ Br_2 -> 2 NOBr takes places through the mechanism given below: NO+ Br_2 Leftrightarrow NOBr_2 (fast) NOBr_2+ NO -> 2 NOBr (slow) The overall order of the reaction is ___________.

Rate K[ NOBr_2] [ NO] [ RDS] k_ eq=frac[ NOBr_2][ NO][ Br_2] => [ NOBr_2]=\ K_ eq[ NO][ Br_2] Rate = K_ eq[ NO][ Br_2] K[ NO] = K_ eq K[ NO]^2[ Br_2] Overall order =2+1=3

The reaction 2 NOBr2 arrow 2 NOBr takes places through ... | (Chemistry)

Rate $\mathrm{K}\left[\mathrm{NOBr}_2\right] \quad[\mathrm{NO}] \quad[\mathrm{RDS}] \\$

$\mathrm{k}_{\mathrm{eq}}=\frac{\left[\mathrm{NOBr}_2\right]}{[\mathrm{NO}]\left[\mathrm{Br}_2\right]} \Rightarrow\left[\mathrm{NOBr}_2\right]$ = $\\ \mathrm{K}_{\mathrm{eq}}[\mathrm{NO}]\left[\mathrm{Br}_2\right] \\$

Rate $=\mathrm{K}_{\mathrm{eq}}[\mathrm{NO}]\left[\mathrm{Br}_2\right] \mathrm{K}[\mathrm{NO}] \\$

$=\mathrm{K}_{\mathrm{eq}} \mathrm{~K}[\mathrm{NO}]^2\left[\mathrm{Br}_2\right]\\$

Overall order =2+1=3

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