The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to h^2 / xma_0^2. The value of 10x is ___________. (a_(0) is radius of Bohr's orbit) (Nearest integer) [Given : pi = 3.14]

mvr = nh / 2pi K.E. = n^2h^2 / 8pi ^2mr^2 = 4h^2 / 8pi ^2m(4a_0)^2 = ( 4 / 8pi ^2 x 16 )h^2 / ma_0^2 => x = 315.507 => 10x = 3155 (nearest integer)

The kinetic energy of an electron in the second Bohr or... | null (Chemistry) | DivineJEE

Exam

Chemistry

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to

{{{h^2}} \over {xma_0^2}}

. The value of 10x is ___________. (a₀ is radius of Bohr's orbit) (Nearest integer) [Given :

\pi

= 3.14]

Correct Answer:

3155

mvr = {{nh} \over {2\pi }}

K.E. = {{{n^2}{h^2}} \over {8{\pi ^2}m{r^2}}} = {{4{h^2}} \over {8{\pi ^2}m{{(4{a_0})}^2}}}

= \left( {{4 \over {8{\pi ^2} \times 16}}} \right){{{h^2}} \over {ma_0^2}}

\Rightarrow

x = 315.507

\Rightarrow

10x = 3155 (nearest integer)

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