On complete combustion 030 g of an organic compound gave 020

Question

On complete combustion 0.30 g of an organic compound gave 0.20 g of carbon dioxide and 0.10 g of water. The percentage of carbon in the given organic compound is _____________. (Nearest integer)

DivineJEE · Accepted Answer

C_xH_y + ( x + y / 4 )O_2 -> x CO_2 + y / 2H_2O Given organic compound C_(x)H_(y)= 0.3 gm Produced carbon dioxide (CO_(2)) = 0.2 gm Produced water (H_(2)O) = 0.1 gm Moles of CO_(2) = 0.2 / 44 Therefore Moles of C atom = 0.2 / 44 Therefore Mass of C atom = 0.2 / 44 x 12 = 0.0545 Moles of H_(2)O = 0.1 / 18 Therefore Moles of H atoms = 0.1 / 18 x 2 Therefore Mass of H atoms = 0.1 x 2 / 18 x 1 = 0.0111 Therefore % of C atom = 0.0545 / 0.3 x 100 = 18%

Explanation

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