Zn | Zn2+(0.1 M) || Ag+ (0.01 M) | Ag
Zn(s) + 2Ag+ ⇌ 2Ag(s) + Zn+2
Ecell0 = EAg + /Ag0 − EZn2 + /Zn0
= 0.80 − ( − 0.76)
= 1.56V
Ecell = 1.56 − 2 0.059 log [Ag + ]2[Zn2 + ]
= 1.56 − 20.059 log (0.01)20.1
= 1.56 − 20.059 × 3
= 1.56 − 0.0885
= 1.4715
= 147.15 × 10 − 2