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A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is _________ $\\times$ $10^{21}$ (Nearest integer).A metal M forms hexagonal close-packed structure. The total number of voids in 0.02 mol of it is _________ $\\times$ $10^{21}$ (Nearest integer).

(Given $\\mathrm{N_A=6.02\\times10^{23}}$)

","solutionTex":"

Number of voids

$$=0.02\\times3\\times6.02\\times10^{23}$$

$$\\simeq36\\times10^{21}$$

","answer":"36","options":[],"metaDescription":"A metal M forms hexagonal closepacked structure The total number of voids in 002 mol of it is x 1021 Nearest integer Given NA602x1023","solutionVideoLink":null,"year":null,"difficulty":"Medium","videoLink":""},"sidebarQuestions":[],"currentSl