A capacitor C is first charged fully with potential | null (Physics)

JEE Mains 2026 21st January Shift 2

Physics

A capacitor C is first charged fully with potential difference of

\mathrm{V}_{0}

and disconnected from the battery. The charged capacitor is connected across an inductor having inductance L . In t s

25 \%

of the initial energy in the capacitor is transferred to the inductor. The value of t is

\_\_\_\_

\frac{\pi \sqrt{L C}}{3}

\frac{\pi \sqrt{\mathrm{LC}}}{6}

\frac{\pi \sqrt{\text { LC }}}{2}

\pi \sqrt{\frac{L C}{2}}

Correct Answer:

\mathrm{U}_{\mathrm{c}_{\mathrm{f}}}=75 \% \mathrm{U}_{\mathrm{c}_{\mathrm{i}}}\\

\mathrm{Q}_{\mathrm{F}}^{2}=\frac{3}{4} \mathrm{Q}_{\mathrm{I}}^{2}\\

\mathrm{Q}_{\mathrm{i}} \cos \omega \mathrm{t}=\frac{\sqrt{3}}{2} \\ \mathrm{Q}_{\mathrm{i}} \Rightarrow \mathrm{t}=\frac{\mathrm{T}}{12}\\

\mathrm{t}=\frac{\pi}{6} \sqrt{\mathrm{LC}}

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