25 mL of an aqueous solution of KCl was found to require 20

Question

25 mL of an aqueous solution of KCl was found to require 20 mL of 1 M $\mathrm{AgNO_3}$ solution when titrated using $\mathrm{K_2CrO_4}$ as an indicator. What is the depression in freezing point of KCl solution of the given concentration? _________ (Nearest integer).

(Given : $\mathrm{K_f=2.0~K~kg~mol^{-1}}$ )

Assume 1) 100% ionization and 2) density of the aqueous solution as 1 g mL $^{-1}$

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DivineJEE · Accepted Answer

25 x M=20 x 1 M =(20 / 25)=(4 / 5)=0.8 \ Delta T_f =( i)( K_ f)( m) \ =(2)(2)((4 / 5))=(16 / 5)=3.2

Explanation

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