100 mL of 005 M KMnO4 solution was consumed in a titration w

Question

10.0 mL of 0.05 M KMnO_(4) solution was consumed in a titration with 10.0 mL of given oxalic acid dihydrate solution. The strength of given oxalic acid solution is _________ x 10^(-2) g/L.(Round off to the nearest integer)

DivineJEE · Accepted Answer

n_(eq) KMnO_(4) = n_(eq) H_(2)C_(2)O_(4) . 2H_(2)Oor, 10 x 0.05 / 1000 x 5 = 10 x M / 1000 x 2Therefore Conc. of oxalic acid solution = 0.125 M= 0.125 x 125 g/L = 15.75 g/L= 1575 x 10^(-2) g/L

Explanation

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