10 mL of gaseous hydrocarbon on combustion gives 40 mL of CO_2( g) and 50 mL of water vapour. Total number of carbon and hydrogen atoms in the hydrocarbon is _________ .

C_x H_y+(x+(y / 4)) O_2 -> x CO_2+(y / 2) H_2 O 10 ml 10(x+(y / 4)) 10 X (10 y / 2) Given 10 x=40 x=4 (10 y / 2)=50 y=10 Hydrocarbon is C_4 H_10

10 mL of gaseous hydrocarbon on combustion gives 40 mL ... | (Chemistry) | DivineJEE

Exam

Chemistry

10 \mathrm{~mL}

of gaseous hydrocarbon on combustion gives

40 \mathrm{~mL}

\mathrm{CO}_2(\mathrm{~g})

and

50 \mathrm{~mL}

of water vapour. Total number of carbon and hydrogen atoms in the hydrocarbon is _________ .

$\mathrm{C}_x \mathrm{H}_y+\left(x+\frac{y}{4}\right) \mathrm{O}_2 \rightarrow x \mathrm{CO}_2+\frac{y}{2} \mathrm{H}_2 \mathrm{O} \\$

$10 \mathrm{ml} \quad 10\left(x+\frac{y}{4}\right) \\$

$10 X \quad \frac{10 y}{2} \\$

Given $10 \mathrm{x}=40 \\$

$\mathrm{x}=4 \\$

$\frac{10 y}{2}=50 \\$

$\mathrm{y}=10 \\$

Hydrocarbon is $\mathrm{C}_4 \mathrm{H}_{10}$

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