On heating a mixture of common salt and K_2 Cr_2 O_7 in equal amount along with concentrated H_2 SO_4 in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are :

4 NaCl+ K_2 Cr_2 O_7+6 H_2 SO_4 -> 2 KHSO_4+2 CrO_2 Cl_2+4 NaHSO_4+3 H_2 O (Chromyl chloride) In Chromyl chloride Cr is in +6 oxidation state.

On heating a mixture of common salt and K 2 Cr 2 O 7 i... | null (Chemistry) | DivineJEE

JEE Mains 2026 21st January Shift 2

Chemistry

On heating a mixture of common salt and

\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}

in equal amount along with concentrated

\mathrm{H}_{2} \mathrm{SO}_{4}

in a test tube, a gas is evolved. Formula of the gas evolved and oxidation state of the central metal atom in the gas respectively are :

\mathrm{CrO}_{2} \mathrm{Cl}_{2}

and +5

\mathrm{CrO}_{2} \mathrm{Cl}_{2}

and +6

\mathrm{Cr}_{2} \mathrm{O}_{2} \mathrm{Cl}_{2}$ and +6

\mathrm{Cr}_{2} \mathrm{O}_{2} \mathrm{Cl}_{2}

and +3

Correct Answer:

4 \mathrm{NaCl}+\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}+6 \mathrm{H}_{2} \mathrm{SO}_{4}\\

\longrightarrow 2 \mathrm{KHSO}_{4}+2 \mathrm{CrO}_{2} \mathrm{Cl}_{2}+4 \mathrm{NaHSO}_{4}+3 \mathrm{H}_{2} \mathrm{O}\\

(Chromyl chloride) In Chromyl chloride Cr is in +6 oxidation state.

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