Mathematics
Let the relations π
1 and π
2 on the set π = {1,2,3, β¦ ,20} be given by π
1 = {(π₯, π¦)βΆ 2π₯ β 3π¦ = 2} and π
2 = {(π₯, π¦) : β5π₯ + 4π¦ = 0}. If π and π be the minimum number of elements required to be added in π
1 and π
2, respectively, in order to make the relations symmetric, then π + π equals
A
10
B
8
C
16
D
12
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