Let A and B be two sets containing 2 elements and 4 elements respectively. The number of subsets of A x B having 3 or more elements is

A=\x, y\ B=\a, b, c, d\ A x B having 2 x 4=8 elementsTotal subsets of A x B=2^8=256\ Therefore Total no. of subsets of A x B having 3 or more elements.\ =256-(1 null set +8 singleton set + ^8 C_2 subset having 2 elements \ =256-1-8-28=219

Let A and B be two sets containing 2 elements and 4 ele... | Relation (Mathematics)

$A=\{x, y\} \\$

$B=\{a, b, c, d\}\\$

$A \times B$ having $2 \times 4=8$ elements

Total subsets of $A \times B=2^8=256$

$\\ \therefore$ Total no. of subsets of $A \times B$ having 3 or more elements.

$\\ =256-$ (1 {null set }+8 { singleton set } + ${ }^8 C_2$ { subset having } 2 { elements }

$\\ =256-1-8-28=219$

Explanation

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