In Carius method, 0.75 g of an organic compound gave 1.2 g of barium sulphate, find percentage of sulphur (molar mass $32 \mathrm{~g} \mathrm{~mol}^{-1}.\\$Molar mass of barium sulphate is $233 \mathrm{~g} \mathrm{~mol}^{-1}$.