A KCl solution of conductivity 014 S m1 shows a resista... | (Chemistry) | DivineJEE

Exam

Chemistry

A KCl solution of conductivity 0.14 S m^{$-$ 1} shows a resistance of 4.19

\Omega

in a conductivity cell. If the same cell is filled with an HCl solution, the resistance drops to 1.03

\Omega

. The conductivity of the HCl solution is ____________

\times

10^{$-$ 2} S m^{$-$ 1}. (Round off to the Nearest Integer).

For KCl solution,

$\\R = \left( {{1 \over K}} \right)\left( {{l \over A}} \right) \Rightarrow {l \over A} = R \times K = 4.19 \times 0.14$

= 0.58

For HCl solution,

$R = \left( {{1 \over K}} \right)\left( {{l \over A}} \right)$

$\Rightarrow K = {{(l/A)} \over R} \\= {{0.58} \over {1.03}} = 0.56 = 56 \times {10^{ - 2}}$ Sm^{$-$ 1}

Select an option to instantly check whether it is correct or wrong.

Download Divine JEE App

Learn on the go with our mobile app. Access courses, live classes, and study materials anytime, anywhere.

Empowering students to achieve their IIT dreams through personalized learning and expert guidance.

contact.divinejee@gmail.com
+91 9137402346
2nd floor, C, 10, Mahant Swami Marg, nr. Pratap Stadium, Chitrakoot, Jaipur, Rajasthan 302021